A square wire loop with sides 0.5 m is placed with its plane perpendicular to the magnetic field. The resistance of the loop is `5Omega`. The rate at
A square wire loop with sides 0.5 m is placed with its plane perpendicular to the magnetic field. The resistance of the loop is `5Omega`. The rate at which the magnetic induction should be changed so that a current of 0.1 A is induced in the loop is
A. 4 T/s
B. 3 T/s
C. 2 T/s
D. 1 T/s
4 views
1 Answers
Correct Answer - C
`e=(dphi)/(dt)`
`IR=(AdB)/(dt)`
`(dB)/(dt)=(IR)/(A)=(0.1xx5)/(0.25)=2T//s`
4 views
Answered