Two resistances are joined in parallel whose equivolent resistance is `3/5Omega`. One of the resistance wire is broken and the effective resistance be
Two resistances are joined in parallel whose equivolent resistance is `3/5Omega`. One of the resistance wire is broken and the effective resistance becomes `3Omega`. The resistance (in ohms) of the wire that got broken was
A. `4/3`
B. 2
C. `6/5`
D. `3/4`
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Correct Answer - D
Resistance of the wire `R_(P)=(R_(1)R_(2))/(R_(1)+R_(2))=(3)/(5)` and `R_(1)=3 Omega`, then
`therefore (3xxR_(2))/(3+R_(2))=(3)/(5)rArr 15 R_(2)=9+3 R_(2)rArr 12 R_(2)=9`
`therefore R_(2)=(3)/(4)Omega`
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