To get a maximum current through a resistance of `2.5Omega` one can use m rows of cells each row having n cells . The internal resistance of each cell

Question

To get a maximum current through a resistance of `2.5Omega` one can use m rows of cells each row having n cells . The internal resistance of each cell

To get a maximum current through a resistance of `2.5Omega` one can use m rows of cells each row having n cells . The internal resistance of each cell is `0.5Omega`. What are the values of m and n, if the total number of cells are 20?
A. `m=2, n=10`
B. m=4, n=5
C. m=5, n=4
D. n=2, m=10

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
Total number of cells `(m+n)=20`
For maximum current, R = nr/m ….(i)
`rArr " " 2.5=n xx0.5//m` or n = 5 m
From Eq. (i), `m xx 5m = 20` , or `m^(2)=4`
`rArr m = 2`, therefore `n = 5xx2=10`

4 views Answered 2023-02-05 15:29