A resistor, `R=300Omega` and a capacitor , `C=25muF` are connected in series with an ac source. The peak value of voltage `(V_0)` and the frequency (f

Question

A resistor, `R=300Omega` and a capacitor , `C=25muF` are connected in series with an ac source. The peak value of voltage `(V_0)` and the frequency (f

A resistor, `R=300Omega` and a capacitor , `C=25muF` are connected in series with an ac source. The peak value of voltage `(V_0)` and the frequency (f) of the source are 150 V and and `50/pi` Hz respectively. Find the peak value of current and the power dissipated in the circuit.

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

IF `omega` is the angular frequency of the ac source, then
`1/(omegaC)=1/(2pitimes50/pitimes25times10^-6)=400Omega`
the peak value of current
`I_0=V_0/(sqrt(R^2+1/(omega^2C^2)))=150/(sqrt(300^2+400^2))=0.3A`
Hence, power dissipated in the circuit
`=1/2I_0^2R=1/2times(0.3)^2times300=13.5W`

4 views Answered 2023-02-05 15:29