The values of `X, Y` and `Z`s in the reaction are repectively: `XMnO_(4)^(-)+YH_(2)SO_(4)rarr2Mn^(2+)+5H_(2)O+9O_(2)+Ze`

Question

The values of `X, Y` and `Z`s in the reaction are repectively: `XMnO_(4)^(-)+YH_(2)SO_(4)rarr2Mn^(2+)+5H_(2)O+9O_(2)+Ze`

The values of `X, Y` and `Z`s in the reaction are repectively:
`XMnO_(4)^(-)+YH_(2)SO_(4)rarr2Mn^(2+)+5H_(2)O+9O_(2)+Ze`
A. 2,6,6
B. 5,2,9
C. 3,5,5
D. 2,6,6

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
For balancing Mn on both sides, multiply `MnO_(4)^(-)` by2. To balance `5H_(2)O`, multiply `H_(2)O_(2)`by 5
`2MnO_(4)^(-)+5H_(2)O_(2)rarr2Mn^(2+)+5H_(2)O+9O_(2)+6e^(-)`
To balance charge on both sides `6e^(-)` have been added on right hand side.

4 views Answered 2023-02-05 15:29