A current is passed through 2 voltmeters connected in series. The first voltmeter contians `XSO_4)(aq)` and second has `Y_(2)SO_(4)`(aq). The relative
A current is passed through 2 voltmeters connected in series. The first voltmeter contians `XSO_4)(aq)` and second has `Y_(2)SO_(4)`(aq). The relative atomic masses of X and Y are in the ratio `2:1`. The ratio of the mass of X liberated to the mass of Y liberated is:
A. `1 : 1`
B. `1 : 2`
C. ` 2 : 1`
D. None of these
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Correct Answer - A
A/c. to `II^(nd)` law
Eq. of X = Eq. of Y
`(W_(1))/(2 M//2) = (W_(2))/(M//1) " " therefore W_(1) = W_(2)`
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