A current is passed through two cells connected in series. The first cell contians `X(NO_(2))_(2)`(aq). The relative atomic masses of X and Y are in t

Question

A current is passed through two cells connected in series. The first cell contians `X(NO_(2))_(2)`(aq). The relative atomic masses of X and Y are in t

A current is passed through two cells connected in series. The first cell contians `X(NO_(2))_(2)`(aq). The relative atomic masses of X and Y are in the ratio 1:2. What is the ratio of the liberated mass of X to that of Y ?
A. `3:2`
B. `1:2`
C. `1:2`
D. `3:3`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
(c ) The oxidation states of X and Y in their respective nitrates are 3 and 2 respectively. The equivalent masses of the metals can be calculated by dividing the respective atomic masses with oxidation states or valences. These are in the ratio `1//3 : 2//2` or `1//3 : 1` or `1:3`

4 views Answered 2023-02-05 15:29