Caculate the ionic radius of a `Cs^(+)` ion, assuming that the cell edge length for CsCl is `0.4123` nm and that the ionic radius of a `Cl^(-)` ion is
Caculate the ionic radius of a `Cs^(+)` ion, assuming that the cell edge length for CsCl is `0.4123` nm and that the ionic radius of a `Cl^(-)` ion is`0.81` nm
A. `0.352` nm
B. `0.116` nm
C. `0.231` nm
D. `0.176` nm
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Correct Answer - D
CsCl has a bcc lattice. So `d_("body")=asqrt(3)`
or `d_("body")=sqrt(3)xx0.4123` nm `=0.7147` nm
Ionic radius of `Cs^(+)=0.3571-0.1761` nm
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