Nickle crystallise in a fcc unit cell with a cell edge length of 0.3524 nm. Calculate the radius of the nicke atom
A. 0.1624 nm
B. 0.1246 nm
C. 0.2164 nm
D. 0.1426nm

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1 Answers

Correct Answer - B
For an fcc lattice , `r=(a)/(2sqrt2)=(0.3524)/(2sqrt2)` = 0.1246nm`

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