The density and edge length values for a crystalline element with fcc lattice are `10 g cm^(-3)` and 400 pm respectively. The number of unit cells in

Question

The density and edge length values for a crystalline element with fcc lattice are `10 g cm^(-3)` and 400 pm respectively. The number of unit cells in

The density and edge length values for a crystalline element with fcc lattice are `10 g cm^(-3)` and 400 pm respectively. The number of unit cells in 32 g of this crystal is
A. `8xx10^23`
B. `5xx10^22`
C. `8xx10^22`
D. `5xx10^23`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
Volume of the unit cell=`a^3="(400 pm)"^3`
`=(400xx10^(-10)cm)^3 =64 xx 10^(-24)cm^3`
Density of the unit cell=`10g//cm^3`
Mass of unit cell=Volume x density
`=64xx10^(-24)xx10=640xx10^(-24) g`
Now, `640xx10^(-24) g -=` 1 unit cell
`therefore 32 g -= 1/(640xx10^(-24))xx32=0.05xx10^24=5xx10^22`

4 views Answered 2023-02-05 15:29