A metal has bcc structure and the edge length of its unit cell is `3.04 Å` . The volume of the vnit cell in `cm^(3)` will be
A. `1.6xx10^(-21)cm^(3)`
B. `2.81xx10^(-23)cm^(3)`
C. `6.02xx10^(-23)cm^(3)`
D. `6.6xx10^(-24)cm^(3)`

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Correct Answer - B
Volume of the unit cell `=a^(3)`
`=(3.04xx10^(-8)cm)^(3)=2.81xx10^(-23)cm^(3)`

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