A galvanometer with a full scale sensitivity of 1 mA requires a `900 Omega` resistor to make a voltmeter reading full scale when 1 V is applied . What series resister is required to make the same galvanometer into 50 V full scale voltmeter ?
A. 59000
B. 49000
C. 49900
D. 4900

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1 Answers

Correct Answer - C
`R_1=(V_1)/(I_g)-G therefore G=100Omega`
Now , `R_2=(V_2)/(I_g)-G=49,900Omega`.

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