The expression for magnetic induction inside a solenoid of length `L` carrying a current `I` and having `N` number of turns is

Question

The expression for magnetic induction inside a solenoid of length `L` carrying a current `I` and having `N` number of turns is

The expression for magnetic induction inside a solenoid of length `L` carrying a current `I` and having `N` number of turns is
A. `(mu_0)/(4pi)(N)/(L)1`
B. `mu NIL`
C. `(mu_0)/(4pi)NIL`
D. `mu_0(NI)/(L)`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`B=mu_0nI=(mu_0NI)/(L) because n=(N)/(L)`

5 views Answered 2023-02-05 15:29