The strength of the magnetic field in a long solenoid having 5000 turns per meter is `3.14X10^(-2)T`. The current flowing through the solenoid is

Question

The strength of the magnetic field in a long solenoid having 5000 turns per meter is `3.14X10^(-2)T`. The current flowing through the solenoid is

The strength of the magnetic field in a long solenoid having 5000 turns per meter is `3.14X10^(-2)T`. The current flowing through the solenoid is
A. 2A
B. 3A
C. 4A
D. 5A

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

A solenoid has length `0.4m`, radius 1 cm and 400 turns of wire. If a current fo 5 A is passed through this solenoid, then what is the magnetic field

2 Answers 7 Views

The magnetic field on the axis of a long solenoid having n turns per unit length and carrying a current is

2 Answers 4 Views

A long solenoid is formed by winding 20 turns `cm^-1`. What current is necessary to produce a magnetic field of 20 mT inside the solenoid?

2 Answers 4 Views

A solenoid is 1.0 metre long and it has 4250 turns. If a current of 5.0 ampere is flowing through it, what is the magnetic field at its centre `[mu_(0

2 Answers 6 Views

A long solenoid has 200 turns per cm and carries a current of 2.5A. The magnetic field at its centre is

2 Answers 5 Views

A long solenoid has 800 turns per metre length of solenoid A currentof 1.6 A flow through it. The magnetic induction at the end of the solenoid on its

2 Answers 5 Views

The magnetic field (B) inside a long solenoid having n turns per unit length and carrying current / when iron core is kept in it is `(mu_o` = permeabi

2 Answers 4 Views

A solenoid of cross-sectional area `2xx 10^(-4)m^(2)` and 900 turns has `0.6A m^(2)` magnetic moment. Then the current flowing through it is

2 Answers 4 Views

A long solenoid having 450 turns per m carries a current of 1.6 A. At the centre of the solenoid a coil of 180 turns with cross sectional area `3.5 cm

2 Answers 4 Views

A long solenoid has 1000 turns. When a current of 4A flows through it, the magnetic flux linked with each turn of the solenoid is `4xx10^(-3)Wb`. The

2 Answers 5 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`I=(B)/(mu_0n)=(3.14xx10^-2)/(4pixx10^-7xx5000)=5A`

4 views Answered 2023-02-05 15:29