A long solenoid has 1000 turns. When a current of 4A flows through it, the magnetic flux linked with each turn of the solenoid is `4xx10^(-3)Wb`. The
A long solenoid has 1000 turns. When a current of 4A flows through it, the magnetic flux linked with each turn of the solenoid is `4xx10^(-3)Wb`. The self-inductance of the solenoid is
A. 3 H
B. 2 H
C. 1 H
D. 4 H
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Correct Answer - C
If the number of turns of the solenoid is N, current through it is I and the magnetic flux linked with each turn of the solenoid is `phi`, then its self-inductance,
`L=(Nphi)/(I)=(1000xx(4xx10^(-3)))/(4)=1H`
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