The self-inductane of a coil having 500 turns is 50 mH. The magnetic flux through the cross-sectional area of the coil while current through it is 8 m

Question

The self-inductane of a coil having 500 turns is 50 mH. The magnetic flux through the cross-sectional area of the coil while current through it is 8 m

The self-inductane of a coil having 500 turns is 50 mH. The magnetic flux through the cross-sectional area of the coil while current through it is 8 mA is found to be
A. `4xx10^(-4)Wb`
B. `0.04Wb`
C. `0.8muWb`
D. 40 m Wb

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
Given, n = 500
L = 50 mH = `5xx10^(-3)` H
and `I = 8mA = 8xx10^(-3)A`
The magnetic flux linked with the coil is
`phi=Li=50xx10^(-3)xx8xx10^(-3)`
`=400xx10^(-6)=4xx10^(-4)Wb`

5 views Answered 2023-02-05 15:29