A body cools at the rate of `0.6^(@)C//s` when it is `40^(@)C` above the surrounding. Then the rate of cooling when it is at `20^(@)C` above the same

Question

A body cools at the rate of `0.6^(@)C//s` when it is `40^(@)C` above the surrounding. Then the rate of cooling when it is at `20^(@)C` above the same

A body cools at the rate of `0.6^(@)C//s` when it is `40^(@)C` above the surrounding. Then the rate of cooling when it is at `20^(@)C` above the same surrounding is
A. `0.2^(@)C//s`
B. `0.3^(@)C//s`
C. `0.15^(@)C//s`
D. `0.4^(@)C//s`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`R_(1)=k(theta_(1)-theta_(2))`
`R_(2)=k(theta_(2)-theta_(0))`
`(R_(2))/(R_(1))=((theta_(2)-theta_(0))/(theta_(1)-theta_(0)))`
`R_(2)=0.3^(@)C//`min.

4 views Answered 2023-02-05 15:29