A body cools at the ratio of `1.2^(@)C//`min when its temperature is more than that of the surrounding by `40^(@)C`. The rate of cooling of the body when its temperature is more than that of surrounding by `25^(@)C` will be
A. `0.75^(@)C`/min
B. `0.25^(@)C`/min
C. `1.25^(@)C`/min
D. `1^(@)C`/min

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1 Answers

Correct Answer - A
`R_(1)=K(theta_(1)-theta_(0)) and R_(2)=k(theta_(2)-theta_(0))`
`(R_(2))/(R_(1))=((theta_(2)-theta_(0)))/((theta_(1)-theta_(0)))=(25)/(40)=(5)/(8)`
`R_(2)=0.75`.

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