A body cools at the rate of `3^(@)C//`min when its temperature is `50^(@)C`. If the temperature of surroundings is `25^(@)C` then the rate of cooling of the body at `40^(@)C` is
A. `2^(@)C`/min
B. `2.4^(@)C`/min
C. `2.8^(@)C`/min
D. `1.8^(@)C`/min

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Correct Answer - D
`R_(1)=k(theta_(1)-theta_(0))`
`R_(2)=k(theta_(2)-theta_(0))`
`(R_(2))/(R_(1))=(40-25)/(50-25)=(15)/(25)=(3)/(5)`
`R_(2)=(3)/(5)xx3=1.8^(@)C//`min.

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