A simple pendulum of length `l_(1)` has frequency 1/4 Hz and another simple pendulum of length `l_(2)` has frequency 1/3 Hz. Then time period of pendu

Question

A simple pendulum of length `l_(1)` has frequency 1/4 Hz and another simple pendulum of length `l_(2)` has frequency 1/3 Hz. Then time period of pendu

A simple pendulum of length `l_(1)` has frequency 1/4 Hz and another simple pendulum of length `l_(2)` has frequency 1/3 Hz. Then time period of pendulum of length `(l_(1)-l_(2))` is
A. 5 s
B. 1 s
C. `sqrt(7) s`
D. `sqrt(12) s`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`(n_(2))/(n_(1))=sqrt((l_(1))/(l_(2)))`
`(3)/(4)=sqrt((l_(1))/(l_(2)))`
`(9)/(16)=(l_(1))/(l_(2)) therefore (l_(2))/(l_(1))=(16)/(9)`
`(l_(2)-l_(1))/(l_(1))=(16-9)/(9)=(7)/(9)`
`sqrt((l_(1)-l_(2))/(l_(1)))=sqrt(7)/(3) therefore T_(1)-T_(2)" is "sqrt(7)`.

5 views Answered 2023-02-05 15:29