A simple pendulum performs simple harmonic motion about X = 0 with an amplitude A and period T. The speed of the pendulum at midway between mean and e

Question

A simple pendulum performs simple harmonic motion about X = 0 with an amplitude A and period T. The speed of the pendulum at midway between mean and e

A simple pendulum performs simple harmonic motion about X = 0 with an amplitude A and period T. The speed of the pendulum at midway between mean and extreme position is
A. `(piAsqrt(3))/(T)`
B. `(piA)/(T)`
C. `(piAsqrt(3))/(2T)`
D. `(3pi^(2)A)/(T)`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`v_(m)=(sqrt(3))/(2)Aomega=(sqrt(3))/(2)A(2pi)/(T)=(sqrt(3)piA)/(T)`

5 views Answered 2023-02-05 15:29