A simple harmonic motion of amplitude A has a time period T. The acceleration of the oscillator when its displacement is half the amplitude is

Question

A simple harmonic motion of amplitude A has a time period T. The acceleration of the oscillator when its displacement is half the amplitude is

A simple harmonic motion of amplitude A has a time period T. The acceleration of the oscillator when its displacement is half the amplitude is
A. `(4pi^(2)A)/(T^(2))`
B. `(2pi^(2)A)/(T^(2))`
C. `-(4pi^(2)A)/(T^(2))`
D. `-(2pi^(2)A)/(T^(2))`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
Acceleration `=-omega^(2)x=(-4pi^(2))/(T^(2))(A)/(2)=(-2pi^(2)A)/(T^(2))`

4 views Answered 2023-02-05 15:29