An automobile egine develops `60 pi` kilowatt of power when it is rotating at the speed of 1800 rev/min, then the torque it can transfer to the wheels is
A. 100 Nm
B. 10 Nm
C. 1000 Nm
D. 1800 Nm

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1 Answers

Correct Answer - C
`P = tau omega " " therefore tau =(60 pi xx 10^(3))/(2pi xx 30)=1000 Nm`.

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