If a wheel has mass 70 kg and radius of gyration 1 m, then the torque required an angular 1 m, then the torque required an angular acceleration of `"2 rev"//s^(2)` will be
A. `140 pi Nm`
B. `380 pi Nm`
C. `180 pi Nm`
D. `280 pi Nm`

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1 Answers

Correct Answer - D
`tau = I alpha = mk^(2) alpha " here " alpha =2xx2 pi rad//s^(2)`

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