A fly wheel of mass 4 kg has moment of inertia `16 kg m^(2)`, then radius of gyration about the central axis perpendicular to its plane is

Question

A fly wheel of mass 4 kg has moment of inertia `16 kg m^(2)`, then radius of gyration about the central axis perpendicular to its plane is

A fly wheel of mass 4 kg has moment of inertia `16 kg m^(2)`, then radius of gyration about the central axis perpendicular to its plane is
A. 1m
B. 2m
C. 4m
D. 16m

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`I = MK^(2)`
`K = sqrt((I)/(m)) = sqrt((16)/(4)) = sqrt(4) = 2`.

5 views Answered 2023-02-05 15:29