A shaft rotating at 6000 rpm is transmitting a power of `2pi` kilowatt. Then the magnitude of the driving torque is

Question

A shaft rotating at 6000 rpm is transmitting a power of `2pi` kilowatt. Then the magnitude of the driving torque is

A shaft rotating at 6000 rpm is transmitting a power of `2pi` kilowatt. Then the magnitude of the driving torque is
A. 10 Nm
B. 5 Nm
C. 1 Nm
D. 0.1 Nm

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`P = tau omega " " therefore tau =(P)/(2pi n)=(2pi xx 10^(3))/(2pi xx10^(-2))=10 Nm`.

4 views Answered 2023-02-05 15:29