The frequency of a particle performing circular motion changes from 60 rpm to 180 rpm in 20 s . Then the angular acceleration is
The frequency of a particle performing circular motion changes from 60 rpm to 180 rpm in 20 s . Then the angular acceleration is
A. `0.1 pi rad //s^(2)`
B. `0.2 pi rad //s^(2)`
C. `0.3 pi rad //s^(2)`
D. `0.4 pi rad //s^(2)`
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Correct Answer - B
`alpha =(2pi(n_(2)-n_(1)))/(t)=(2pi(3-1))/(20)`
`=0.2pi rad//s^(2)`
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