A solid cylinder of radius 0.5 m and mass 50 kg is rotating at 300 rpm. Then the torque which will bring it to rest in 5 seconds is

Question

A solid cylinder of radius 0.5 m and mass 50 kg is rotating at 300 rpm. Then the torque which will bring it to rest in 5 seconds is

A solid cylinder of radius 0.5 m and mass 50 kg is rotating at 300 rpm. Then the torque which will bring it to rest in 5 seconds is
A. `25 pi Nm`
B. `(25 pi)/(2)Nm`
C. `50 pi Nm`
D. `100 pi Nm`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`tau = I alpha =(I(omega_(2)-omega_(1)))/(t)`

4 views Answered 2023-02-05 15:29