A particle is moving on a circular path with constant speed v then the change in its velocity after it has desceibed an angle of `60^(@)` will be
A. `vsqrt2`
B. 0
C. variable
D. 2v

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1 Answers

Correct Answer - C
`Deltav=2v sin 60//2`
`2vxx(1)/(2)=v`

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