A particle goes round a circular path with uniform speed v.After describing half the circle, what is the change in its centripetal acceleration?
A particle goes round a circular path with uniform speed v.After describing half the circle, what is the change in its centripetal acceleration?
A. `(v^(2))/(r)`
B. `(2v^(2))/(r)`
C. `(2v^(2))/(pir)`
D. `(v^(2))/(pir)`
4 views
1 Answers
Correct Answer - B
`Delta a =2a "sin" (theta)/(2)=(2v^(2))/(r)xx1=(2v^(2))/(r) m//s`.
4 views
Answered