Phosphorus pentachloride dissociates as follows in a closed reaction vessel. `PCl_5(g) hArr PCl_3(g) +Cl_2(g)` If total pressure at equilibrium of the
Phosphorus pentachloride dissociates as follows in a closed reaction vessel.
`PCl_5(g) hArr PCl_3(g) +Cl_2(g)`
If total pressure at equilibrium of the reactions mixture is P and degree of dissociation of `PCl_5`is x, the partial pressure of `PCl_3` will be:
A. `(x/(x+1))P`
B. `((2x)/(1-x))P`
C. `(x/(x-1))P`
D. `(x/(1-x))P`
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Correct Answer - A
`{:(PCl_(5(g)) hArr , PCl_(3(g)) ,+ Cl_(2(g))),("(1-x)","(x)","(x)"):}`
`P_(PCl_3)=(x/(1+x))xxP`
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