Nitrogen dioxide `(NO_(2))` dissociates into nitric oxide (NO) and oxygen `(O_(2))` as follows `NO_(2) to 2NO + O_(2)` If the rate of decrease of conc
Nitrogen dioxide `(NO_(2))` dissociates into nitric oxide (NO) and oxygen `(O_(2))` as follows
`NO_(2) to 2NO + O_(2)`
If the rate of decrease of concentration of `NO_(2)` is `6.0 xx 1-^(12)` mol `L^(-1) s^(-1)`. What will be the rate of increase of concentration of `O_(2)`?
A. `3 xx 10^(-12) mol L^(-1) s^(1)`
B. `6 xx 10^(-12) mol L^(-1) s^(-1)`
C. `1 xx 10^(-12 mol L^(-1) s^(1)`
D. `1.5 xx 10^(-12) mol L^(-1) s^(1)`
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Correct Answer - A
For the reaction, `2NO_(2) to 2NO + O_(2)`
`-(1)/(2) (d[NO_(2)])/(dt) = (1)/(2) (d[NO])/(dt) = (d[O_(2)])/(dt)`
`- (d[NO_(2)])/(dt) = 6 xx 10^(-12) mol L^(-1) s^(-1)`
`(d[O_(2)])/(dt) = 3 xx 10^(-12) mol L^(-1) s^(-1)`
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