310 J of heat is required to rise the temperature of 2 moles of an ideal gas at constant pressure from `25^(@)C` to `35^(@)C`. The amount of heat requ

Question

310 J of heat is required to rise the temperature of 2 moles of an ideal gas at constant pressure from `25^(@)C` to `35^(@)C`. The amount of heat requ

310 J of heat is required to rise the temperature of 2 moles of an ideal gas at constant pressure from `25^(@)C` to `35^(@)C`. The amount of heat required to raise the temperature of the gas through the same range at constant volume, is
A. 384 J
B. 144 J
C. 276 J
D. 452 J

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
At constant pressure,
Heat required `=nC_(p)DeltaT`
`rArr" " 310=2xxC_(p)xx(35-25)`
`rArr" " C_(p)=(310)/(20)=15.5J "mol" ^(-1)K^(-1)`
Similarly ,at constant volume ,
Heat required `nC_(v)DeltaT`
`=2(C_(p)-R)xx(35-25)" " [becauseC_(p)-C_(v)=R] `
`=2xx(15.5-8.3)xx10`
`=2xx7.2xx10=144 J`

4 views Answered 2023-02-05 15:29