if quantity of heat 1163.4 J supplied to one mole of nitrogen gas , at room temperture at constant pressure , then the rise in temperature is

Question

if quantity of heat 1163.4 J supplied to one mole of nitrogen gas , at room temperture at constant pressure , then the rise in temperature is

if quantity of heat 1163.4 J supplied to one mole of nitrogen gas , at room temperture at constant pressure , then the rise in temperature is
A. 54 K
B. 28 K
C. 65 K
D. 8 K

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
Heat given to the gas at room temperture and at constant temperature , `Q=nCpDeltaT`
`therefore1163.4=1xx(7)/(2)RxxDeltaT" " (becauseC_(p)=(7)/(2)R " for diatomic gas")`
`"or"" " DeltaT=(2xx1163.4)/(7xx8.31)" " (because R=8.31J"mol"^(-1)K^(-1))`
`"or " DeltaT=40K`

4 views Answered 2023-02-05 15:29