The electric field that can balance a charged particle of mass `3.2xx10^(-27)`kg is (Given that the charge on the particle is `1.6xx10^(-19)C`)
A. `19.6xx10^(-8)NC^(-1)`
B. `20xx10^(-6)NC^(-1)`
C. `19.6xx10^(8)NC^(-1)`
D. `20xx10^(6)NC^(-1)`

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Correct Answer - A
Here, `m=3.2xx10^(-27)kg,e=1.6xx10^(-19)C,g=9.8ms^(-2)`
`As" "E=F/q=(mg)/e=(3.2xx10^(-27)xx9.8)/(1.6xx10^(-19))=19.6xx10^(-8)NC^(-1)`

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