The specific charge of a proton is `9.6xx10^(7)"C kg"^(-1)`. The specific charge of an alpha particle will be

Question

The specific charge of a proton is `9.6xx10^(7)"C kg"^(-1)`. The specific charge of an alpha particle will be

The specific charge of a proton is `9.6xx10^(7)"C kg"^(-1)`.
The specific charge of an alpha particle will be
A. `9.6xx10^(7)"C "kg^(-1)`
B. `19.2xx10^(7)"C "kg^(-1)`
C. `4.8xx10^(7)" C "kg^(-1)`
D. `2.4xx10^(7)" C "kg^(-1)`.

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

if `(tanalpha-i(sin ""(alpha)/(2)+cos ""(alpha)/(2)))/(1+2 i sin ""(alpha)/(2))` is purely imaginary then `alpha` is given by -

2 Answers 4 Views

निम्नलिखित में दिए गए प्रत्‍येक आव्यूहों के व्युत्‍क्रम (जिनका अस्तित्व हो) ज्ञात कीजिए। `[(1,0,0),(0,cos alpha,sin alpha),(0, sin alpha,-cos alpha)]`

2 Answers 5 Views

`|(cos alpha cos beta, cos alpha sin beta,-sin alpha),(-sin beta, cos beta, 0),(sin alpha cos beta,sin alpha sin beta, cos alpha)|` का मान ज्ञात कीजिए

2 Answers 5 Views

सारणिकों के गुणधर्मों के प्रयोग से सिद्ध कीजिए कि - `|(alpha,beta,gamma),(alpha^2,beta^2,gamma^2),(beta+gamma,gamma+alpha,alpha+beta)|=(alpha - beta )

2 Answers 5 Views

Find the coefficient of `alpha^(6)` in the product `(1+alpha+alpha^(2))(1+alpha+alpha^(2))(1+alpha+alpha^(2)+alpha^(3))` `(1+alpha)(1+alpha)(1+alpha)`

2 Answers 4 Views

The electric field that can balance a charged particle of mass `3.2xx10^(-27)`kg is (Given that the charge on the particle is `1.6xx10^(-19)C`)

2 Answers 5 Views

दर्शाइए कि आव्यूह `[(cos alpha, sin alpha, 0),(-sin alpha, cos alpha, 0),(0,0,1)]` का व्युत्क्रम `[(cos alpha, - sin alpha,0),(sin alpha, cos alpha, 0

2 Answers 5 Views

If the electronic charge `e=1.6xx10^(-19)C and ` the specific charge e/m off electron is `1.76xx10^(11)C(kg)^(-1)` then calculate the mass m of the el

2 Answers 4 Views

Calculate the binding energy of an `alpha`-particle. Given that mass of proton = 1.0073 u, mass of neutron = 1.0087 u, and mass of `alpha`- particle =

2 Answers 4 Views

If alpha particle, proton and electron move with the same momentum, them their respective de Broglie wavelengths `lamda_(alpha),lamda_(p),lamda_(e)` a

2 Answers 4 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
Specific charge of proton`=((e)/(m))_(p)=9.6xx10^(-7)Ckg^(-1)`
specific charge on `alpha`-particle,
`((q)/(m))_(alpha)=(2e)/(m)=(1)/(2)(e)/(mm)_(p)=(1)/(2)xx9.6xx10^7`
`=4.8xx10^(7)Ckg^(-1)`

4 views Answered 2023-02-05 15:29