The electric field intensity at point near and outside the surface of a charged conductor of any shape is `E_(1)` the electric field intensity due to

Question

The electric field intensity at point near and outside the surface of a charged conductor of any shape is `E_(1)` the electric field intensity due to

The electric field intensity at point near and outside the surface of a charged conductor of any shape is `E_(1)` the electric field intensity due to uniformly charged infinite thin plane sheet is `E_(2)` the relation between `E_(1)` and `E_(2)` is
A. `2E_(1)=E_(2)`
B. `E_(1)=E_(2)`
C. `E_(1)=2E_(2)`
D. `E_(1)=4E_(2)`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - C
Electric field intensity at a point mear and outside the surface of any charged conductor is given by
`E_(1)=(sigma)/(epsilon_(0))" …(i)"`
where, `sigma` is charge density (charge per unit area) at a point.
Electric field intensity due to uniformaly charged infinite thin plane sheet is given by
`E_(2)=(sigma)/(2epsilon_(0))" ...(ii)"`
From Eqs. (i) and (ii), we have
`E_(1)=(2)/(2)xx(sigma)/(epsilon_(0))=2xxE_(2)`
`rArr" "E_(1)=2E_(2)`