A charged particle of mass 0.003 g is held stationary in space by placing it in a downward direction of electric field of `6xx10^(4)NC^(-1)`. Then, th

Question

A charged particle of mass 0.003 g is held stationary in space by placing it in a downward direction of electric field of `6xx10^(4)NC^(-1)`. Then, th

A charged particle of mass 0.003 g is held stationary in space by placing it in a downward direction of electric field of `6xx10^(4)NC^(-1)`. Then, the magnitude of charge is
A. `5xx10^(-4)C`
B. `5xx10^(-10)C`
C. `5xx10^(-6)C`
D. `5xx10^(-9)C`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
By using, `qE=mg rArr q=(mg)/(E)`
`=(3xx10^(-6)xx10)/(6)=5xx10^(-10)C`

4 views Answered 2023-02-05 15:29