If the wavelength of photon emitted due to transition of electron from third orbit to first orbit in a hydrogen atom is `lambda` then the wavelength of photon emitted due to transition of electron from fourth orbit to second orbit will be
A. `(128)/(27)lambda`
B. `(25)/(9)lambda`
C. `(36)/(7)lambda`
D. `(125)/(11)lambda`

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1 Answers

Correct Answer - A
`13.6 z^(2) ((1)/(1^(2))-(1)/(3^(2))) =(hc)/(lambda)`
`13.6z^(2) ((1)/(2^(2))-(1)/(4^(2))) = (hc)/(lambda_(1))`
On division, `((8)/(9))/((3)/(16)) = (lambda_(1))/(lambda)`
`:. lambda_(1) = (128)/(27)lambda`

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