A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of m radiation emitted when the atom make a transition from the u

Question

A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of m radiation emitted when the atom make a transition from the u

A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of m radiation emitted when the atom make a transition from the upper level to the lower level ?

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Here `E=2.3eV = 2.3xx1.6xx10^(-19) J`
As E=hV
`therefore v=€/(h)=(2.3xx1.6xx10^(-19))/(6.6xx10^(-34))=5.6xx10^(4) Hz`

4 views Answered 2023-02-05 15:29