The ratio of energy of emitted radiation of a black body at `27^(@)C` and `927^(@)C` is
The ratio of energy of emitted radiation of a black body at `27^(@)C` and `927^(@)C` is
A. `1:4`
B. `1:16`
C. `1:8`
D. `1:256`
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Correct Answer - D
`(E_(1))/(E_(2))=((T_(1))/(T_(2)))^(4)=((300)/(1200))^(4)=((1)/(4))^(4)=(1)/(256)`.
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