The process is spontaneous at the given temperature, if

(a) ΔH is +ve and ΔS is –ve

(b) ΔH is-ve and ΔS is +ve

(c) ΔH is +ve and ΔS is +ve

(d) ΔH is +ve and ΔS is equal to zero.

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1 Answers

(b) ΔG=ΔH-TΔS (Gibbs energy equation). When, ΔH is –ve, but TΔS is +ve → ΔG will be (-ve) [Highly spontaneous]

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