If an endothermic reaction is non-spontaneous at freezing of water and becomes feasible at its boiling point,
If an endothermic reaction is non-spontaneous at freezing of water and becomes feasible at its boiling point, then
(a) ΔH is –ve, ΔS is +ve
(b)ΔH and ΔS both are +ve
(c) ΔH and ΔS both are –ve
(d)ΔH is +ve, ΔS is _ve.
4 views
1 Answers
(b) For endothermic reaction, ΔH=+ve. Now, ΔG=ΔH-TΔS
ΔG will be +ve when ΔH and ΔS both are +ve and temperature is low so that ΔH> (-TΔS). ΔG will be –ve When ΔH and ΔS both are +ve and temperature is high so that ΔH<(-TΔS).
4 views
Answered