At a certain temperature ‘T’, the endothermic reaction A---> B proceeds virtually to the end. Determine: (i) sign of ΔS for this reaction
At a certain temperature ‘T’, the endothermic reaction
A---> B proceeds virtually to the end. Determine:
(i) sign of ΔS for this reaction
(ii) sign of ΔG for the reaction B-----> A at the temperature T, and
(iii) the possibility of reaction B------> A proceeding at a low temperature.
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(i) Energy factor opposes .So enthalpy factor must favour , i.e. ,ΔS must be positive.
(ii) For A----> B , ΔG is –ve, therefore, for B----->A, ΔG will be +ve.
(iii) For B-----> A, ΔH = - ve and ΔS is also –ve , i.e. ,Δs opposes the process but at low temp., TΔS may be so low that ΔH is greater in magnitude then TΔS and the process will be spontaneous.
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