If an endothermic reaction is non-spontaneous at freezing point of water and becomes feasible at its boiling point, then
(a) ΔH is –ve, ΔS is +ve
(b) ΔH and ΔS both are +ve
(c) ΔH and ΔS both are –ve
(d) ΔH is +ve, ΔS is –ve
(b) : For endothermic reaction, ΔH = +ve
Now, ΔG = ΔH – TΔS
For nonspontaneous
reaction, ΔG should be positive
Now ΔG is positive at low temperature if ΔH is positive.
ΔG is negative at high temperature if ΔS is positive.
(c) : According to Raoult’s law equimolal solutions of all the substances in the same solvent will show equal elevation in boiling points as well as equal depression in freezing...
(i) Energy factor opposes .So enthalpy factor must favour , i.e. ,ΔS must be positive.
(ii) For A----> B , ΔG is –ve, therefore, for B----->A, ΔG will be +ve.
(iii) For B----->...
(b) For endothermic reaction, ΔH=+ve. Now, ΔG=ΔH-TΔS
ΔG will be +ve when ΔH and ΔS both are +ve and temperature is low so that ΔH> (-TΔS). ΔG will be –ve When...