A shell is fired from a cannon with a velocity V at as angle θ with the horizontal direction.

Question

A shell is fired from a cannon with a velocity V at as angle θ with the horizontal direction.

A shell is fired from a cannon with a velocity V at as angle θ with the horizontal direction. At the highest point in its path, it explodes into two pieces of equal masses. One of the pieces retraces its path to the caimott, The speed of the other piece immediately after the explosion is
(a) 3Vcosθ

(b) 2Vcosθ

(c) 3/2Vcosθ

(d) Vcosθ

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Related Questions

From a rifle of mass 4 kg, a bullet of mass 50 g is fired with an initial velocity of 35 m s- '1. Calculate the initial recoil velocity of the rifle.

1 Answers 9 Views

A projectile is projected at an angle ø(>45o ) with an initial velocity u. the time t at which its horizontal component will equal

1 Answers 4 Views

The range of a projectile fired at an angle of 15° is 50 m. If it is fired with the same speed at an angle of 45°, its range will be

1 Answers 5 Views

A boy of mass M is applying a horizontal force to slide a box of mass M' on a rough horizontal surface.

1 Answers 5 Views

A uniform sphere is placed on a smooth horizontal surface and a horizontal force F is applied on it

1 Answers 5 Views

Water is flowing in streamliries motion through a tube with its axis horizontal. Consider two points A and B in the tube at the same horizontal level.

1 Answers 8 Views

The range of a projectile fired at an angle of 15° is 50m.

1 Answers 4 Views

A boy of mass M is applying a horizontal force to slide a box of mass M' on a rough horizontal surface,

1 Answers 5 Views

Write the relationship between angle of incidence ‘i’, angle of prism ‘A’ and angle of minimum deviation for a triangular prism.

1 Answers 7 Views

Two men are walking along a horizontal straight line in the same direction. The man in front walks at a speed 1.0ms^–1

1 Answers 5 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

(a) The speed of the other piece immediately after the explosion is 3Vcosθ .

Explanation:

Component of the velocity in horizontal direction = V.cosθ. Hence the momentum before the explosion in the horizontal direction = 2m.Vcosθ. Since one part retraces its path to canon, so its velocity immediately after the explosion = -V.cosθ and let the speed of the other piece be V'. From the conservation principle of the momentum, mV'-mV.cosθ = 2m.Vcosθ

→V' = 3Vcosθ