A projectile is projected at an angle ø(>45o ) with an initial velocity u. the time t at which its horizontal component will equal
A projectile is projected at an angle ø(>45o ) with an initial velocity u. the time t at which its horizontal component will equal the vertical component in magnitude is:-
a) t=u/g(cosø-sinø). b) t=u/g(cosø+sinø).
c) t=u/g(sinø-cosø). d) t=u/g(sin2ø-cos2ø).
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Correct answer is (c)
Explanation:
Let the angle be ø,
Aat any time t,
in the x-direction.
Vx = ucos(ø)
in y-direction.
Vy = usinø – gt
Now Vx = Vy (given)
usinø – gt = ucosø
u(sinø – cosø) = gt
t = [u(sinø – cosø)]/g
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