The range of a projectile fired at an angle of 15° is 50 m. If it is fired with the same speed at an angle of 45°, its range will be
The range of a projectile fired at an angle of 15° is 50 m. If it is fired with the same speed at an angle of 45°, its range will be
(a) 25 m
(b) 37 m
(c) 50 m
(d) 100
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(d) 100 m.
Explanation:
In the first case Range = 50 = (u2 /g) Sin(2x15°) = (u2 /2g) => (u2 /g)=100 In the second case range = (u2 /g) Sin(2x45°) = (u2 /g) Sin90° =100 m
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