The sum of the ages of a man and his son is 45 years. Five years ago, the product of their ages was four times the man’s age at the time.

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The sum of the ages of a man and his son is 45 years. Five years ago, the product of their ages was four times the man’s age at the time.

The sum of the ages of a man and his son is 45 years. Five years ago, the product of their ages was four times the man’s age at the time. Find their present ages.

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Salim Ahmed Kawsar · Answer 1 · Feb 05, 2023 15:29:48

Let the present age of the son be x years
Given that,
sum of present ages of man and his son is 45 years.

⇒ Man’s present age = (45 – x)years
And also given that, five years ago, the product of their ages was four times the man’s age at the time.

⇒ Man’s age before 5 years = (45 – x – 5) years = (40 – x) years
And son’s age before 5 years = (x – 5) years
But, given that (40 – x) (x – 5) = 4(40 – x)

⇒ x – 5 = 4
⇒ x = 9 years
⇒ Son’s present age ⇒ x = 9 years
Now, Man’s present age ⇒ (45 – x) years = (45 – 9) years =36 years
∴ The present ages of man and son are 36 years and 9 years respectively.

Salim Ahmed Kawsar · Answer 2 · Feb 05, 2023 15:29:48

Let the present ages of the man and son be ‘a’ and ‘b’ respectively.

Given, sum of the ages of a man and his son is 45 years.

⇒ a + b = 45 .............(1)

Ans, five years ago, the product of their ages was four times the man’s age at the time.

⇒ (a – 5)(b – 5) = 4(a – 5)

⇒ b – 5 = 4

⇒ b = 9 years

Thus, a = 45 – 9 = 36 years

The sum of the ages of a man and his son is 45 years. Five years ago, the product of their ages was four times the man’s age at the time.

2 Answers