Aman’s age is three times his son’s age. Ten years ago he was five times his son’s age. Find their present ages.

Son age be x
Aman age is 3x
ten years ago
son age x-10
aman age 3x -10
A/Q
5(x-10) = 3x -10
 5x -50 = 3x - 10
2x = 40
x =20
3x=60

son present age =20
aman present age = 60

Let Aman’s son’s age be x years. Therefore, Aman’s age will be 3x years. Ten years ago, their age was (x − 10) years and (3x − 10) years respectively. According to the question,

10 years ago, Aman’s age = 5 × Aman’s son’s age 10 years ago

3x - 10 = 5(x - 10)

3x - 10 = 5x - 50

Transposing 3x to R.H.S and 50 to L.H.S, we obtain

50 - 10 = 5x - 3x

40 = 2x

Dividing both sides by 2, we obtain

20 = x

Aman’s son’s age = x years = 20 years

Aman’s age = 3x years = (3 × 20) years = 60 years

present age of aman=3x
present age of his son=x
According to Question
3x-10=5(x-10)
3x-10=5x-50
2x=40
x=20 years
present age of aman = 3x=3*20= 60years
present age of his son=x=20 years.